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Statements

Subject Item
dbr:John_Selman
rdf:type
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rdfs:label
John Selman John Selman
rdfs:comment
John Selman, né le 16 novembre 1839 et mort le 6 avril 1896 est un personnage ayant assassiné le hors-la-loi John Wesley Hardin le 19 août 1895 dans un saloon d'El Paso. John Henry Selman (November 16, 1839 – April 6, 1896) was sometimes identified as an outlaw and sometimes a working lawman of the Old West. He is best known as the man who shot John Wesley Hardin in the Acme Saloon in El Paso, Texas, on August 19, 1895.
foaf:name
John Selman
dbp:name
John Selman
foaf:depiction
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dbo:birthPlace
dbr:Madison_County,_Arkansas
dbo:deathPlace
dbr:Texas dbr:El_Paso
dbp:deathPlace
El Paso, Texas, USA
dbo:deathDate
1896-04-06
dbp:birthPlace
Madison County, Arkansas, USA
dbo:birthDate
1839-11-16
dcterms:subject
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dbo:thumbnail
n5:JohnSelman.jpg?width=300
dbp:birthDate
1839-11-16
dbp:birthName
John Henry Selman Sr.
dbp:deathDate
1896-04-06
dbp:nationality
American
dbp:occupation
Lawman and outlaw
dbo:abstract
John Selman, né le 16 novembre 1839 et mort le 6 avril 1896 est un personnage ayant assassiné le hors-la-loi John Wesley Hardin le 19 août 1895 dans un saloon d'El Paso. John Henry Selman (November 16, 1839 – April 6, 1896) was sometimes identified as an outlaw and sometimes a working lawman of the Old West. He is best known as the man who shot John Wesley Hardin in the Acme Saloon in El Paso, Texas, on August 19, 1895.
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dbo:birthName
John Henry Selman Sr.
dbo:birthYear
1839-01-01
dbo:deathYear
1896-01-01
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dbr:Gunshot_wound
dbo:occupation
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wikipedia-en:John_Selman