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  • Rule: ActivityStreamsMapasEquivalentb3sb3sifpdbprdf-labelfacetshttp://dbpedia.org/resource/inference/rules/dbpedia#http://dbpedia.org/resource/inference/rules/opencyc#http://dbpedia.org/resource/inference/rules/umbel#http://dbpedia.org/resource/inference/rules/yago#http://dbpedia.org/schema/property_rules#http://www.ontologyportal.org/inference/rules/SUMO#http://www.ontologyportal.org/inference/rules/WordNet#http://www.w3.org/2002/07/owl#ldpoplwebskos-transurn:det:rdf:labelvirtrdf-labelvirtrdf-urlNone
    
  • Inverse Functional Properties: Disabled (fastest) Apply to subjects only Apply to objects only Apply to both subjects and objects
  • "Same As": Disabled (fastest) Apply to subjects only Apply to objects only Apply to both subjects and objects (recommended) Apply to subjects, objects and predicates (not recommended on big datasets) Apply to predicates only (special use cases only)

About: Rosanna Fratello     Goto   Sponge   NotDistinct   Permalink

An Entity of Type : yago:WikicatPeopleFromTheProvinceOfFoggia, within Data Space : dbpedia.org associated with source document(s)

Type: Thingfoaf:Personpersondul:NaturalPersonEukaryotePersonHumanAnimalanimaleukaryotespeciesschema:Personyago:WikicatLivingPeopleyago:Actor109765278yago:Actress109767700yago:Artist109812338yago:CausalAgent100007347yago:Creator109614315yago:Entertainer109616922yago:LivingThing100004258yago:Musician110339966yago:Musician110340312yago:Object100002684yago:Organism100004475yago:Performer110415638yago:Person100007846yago:PhysicalEntity100001930yago:WikicatItalianFemaleSingersyago:WikicatItalianFilmActressesyago:YagoLegalActoryago:YagoLegalActorGeomusical artistyago:Singer110599806yago:Whole100003553yago:WikicatPeopleFromTheProvinceOfFoggia New Facet based on Instances of this Class

Rosanna Fratello (born 26 March 1951) is an Italian singer and actress.